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6n^2+43n+7=0
a = 6; b = 43; c = +7;
Δ = b2-4ac
Δ = 432-4·6·7
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-41}{2*6}=\frac{-84}{12} =-7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+41}{2*6}=\frac{-2}{12} =-1/6 $
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